13x/2x^2=65

Solution for 13x/2x^2=65 equation:

13x/2x^2=65

We move all terms to the left:

13x/2x^2-(65)=0


Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


13x-65*2x^2=0

Wy multiply elements

-130x^2+13x=0

a = -130; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-130)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-130}=\frac{-26}{-260}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-130}=\frac{0}{-260}
=0
$